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The position vector of a particle is vec...

The position vector of a particle is `vecr=4t^(2)hati+2thatj+3hatk`. The speed of the particle t=5s is

A

`42ms^(-1)`

B

3s

C

`3ms^(-1)`

D

`40ms^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A, B, D

`vecr=4t^(2)hati+2thatj+3hatk`
Speed `v=(dvecr)/(dt)=8thati+2hatj` , at t=5s `v=40+2=42`
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