During a projectile motion if the maximum height equals the horizontal range,then the angle of projection with the horizontal is :

Options

A. `32^(@)`
B. `48^(@)`
C. `76^(@)`
D. `84^(@)`

Explanation

`H_(max)=` horizontal range
`(u^(2)sin^(2)theta)/(2g)=(u^(2)sin2theta)/(g)`
`(sin^(2)theta)/(2)=2sinthetacostheta`
`sintheta=4costheta`
`:.tantheta=4" "theta=76^(@)`