What is the pressure inside the drop of mercury of radius 3.00 mm at room temperature ? Surface tension of mercury at that temperature (20 °C) is 4.65 x 10-1 N m_1. The atmospheric pressure is 1.01 x 105 Pa. Also give the excess pressure inside the drop.

Explanation

Here, surface tension, T = 4.65 x 10-1 Nm-1
Radius of drop, r =3.00 mm = 3 x 10-3 m.
Outside pressure, p0 = 1.01 x 105 Pa.
Using the relation,