Equipotential Surface (समविभव सतह)|Flux ( विद्युत फ्लक्स)|Gauss Theorem ( गॉस प्रमेय)|Capacitor (संधारित्र)|OMR

वैद्युत फ्लक्स तथा गॉस प्रमेय|प्रश्न|OMR|Summary

वैधुत फ्लक्स|उदाहरण|गॉस प्रमेय|OMR|Summary

Equipotential Surface|Properties Of Equipotential Surface|Capacitor|OMR

Revision|विद्युत फ्लक्स|गाउस प्रमेय|गाउसीय पृष्ठ के अभिलाक्षणिक गुण तथा गाउस के नियम से सम्बंधित महत्वपूर्ण बिंदु|OMR|Summary

A charge q is situated at the centre of an imaginary hemispherical surface, as shown in figure. Using gauss's theorem and symmetry considerations, determine the electric flux due to this charge through the hemisphere surface.

The law goverening electrostatics is coulomb's law.In priciple coulomb's law can be used to compute electric field due to any charge configuation .In pracitce however it is a formidable task to compute electric field due to uniform charge distributions .For such cases Gauss proposed a theorem which states that ointbar(E).bar(ds)=(q)/(epsilon_(0)) where ds is an element of area directed across the outward normal for the surface at every point .The integral is called electric flux.Any convenient surface that we choose to evalute the surface integral is called the Gaussian surface. The SI unit of electric flux is

The law goverening electrostatics is coulomb's law.In priciple coulomb's law can be used to compute electric field due to any charge configuation .In pracitce however it is a formidable task to compute electric field due to uniform charge distributions .For such cases Gauss proposed a theorem which states that ointbar(E).bar(ds)=(q)/(epsilon_(0)) where ds is an element of area directed across the outward normal for the surface at every point .The integral is called electric flux.Any convenient surface that we choose to evalute the surface integral is called the Gaussian surface. Gauss throrem in electrostatics states that electric flux oint(E.ds)=(q)/(epsilon_(0)) where S is the Gaussian surface ,the electric field E is due to all the charges

The law goverening electrostatics is coulomb's law.In priciple coulomb's law can be used to compute electric field due to any charge configuation .In pracitce however it is a formidable task to compute electric field due to uniform charge distributions .For such cases Gauss proposed a theorem which states that ointbar(E).bar(ds)=(q)/(epsilon_(0)) where ds is an element of area directed across the outward normal for the surface at every point .The integral is called electric flux.Any convenient surface that we choose to evalute the surface integral is called the Gaussian surface. Consider a uniform electric field E=3xx10^(3)hat(i)NC^(-1) what is the flux thorugh a square of side 10 cm whose plane is parallel to the y-z plane?

A physics teacher explains Gauss's theorem in electrostatics and Gauss's theorem in magnetism to his students in a class. He tells them that total normal electric flux over a closed surface in vacuum is phi_e=(Q)/(in_0) , where Q is algebraic sum of charges inside the surface. Further, total normal magnetic flux over a closed surface in vacuum is always zero. The teacher emphasises that this is because in magnetism, poles always exist in unlike pairs of equal strengh, i.e., isolated magnetic poles called monopoles do not exist. Read the above passage and answer the following questions: (i) What are the implications of Gauss's theorem in magnetism in day to day life? (ii) Two magnetic dipoles of moments 5Am^2 and 3Am^2 oriented along opposite directions are enclosed in a surface. What is total normal magnetic flux over this surface? (iii) Two point charges +4q and -q are enclosed in a surface in vacuum, and third charge 5q lies outside the surface. What is total normal electric flux over the surface?