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The figure showsn tow parallel equipoten...

The figure showsn tow parallel equipotential surface A and B kept at a small distance 'r' a part from each other. A point chang of Q coumomb is taken from the surface A to B. The amount of net work done will be

A

`W=(-1)/(4pi epsi_(0)) (q)/(r)`

B

`W=(1)/(4pi epsi_(0)) (q)/(r^(2))`

C

`W=(-1)/(4pi epsi_(0)) (q)/(r^(2))`

D

zero

Text Solution

Verified by Experts

The correct Answer is:
D
`W=(V_(A)-V_(B))q`
`:. V_(A)=V_(B)` for equipotential suface `W=Oxxq=0`
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