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The electric potential V as a function o...

The electric potential V as a function of distance x (meters) is given by `V=(5x^(2)+10x-9)` volt. The value of electric field at a point x=1m is

A

`20 Vm^(-1)`

B

`6 Vm^(-1)`

C

`11 Vm^(-1)`

D

`-23 Vm^(-1)`

Text Solution

Verified by Experts

The correct Answer is:
A
We know, `E=(dV)/(dx)`
`V=5x^(2)+10x-9`
Differentiating w.r.t .x. on both sides
`(dV)/(dx)=10x+10=E`
At a point `x=1 " " m, (dV)/(dx)= 10 (1)+10`
`:. E=(dV)/(dx)=20 Vm^(-1)`
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