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Three point A, B & C lie in a uniform el...

Three point A, B & C lie in a uniform electric field (E) of `5xx10^(3)NC^(-1)`. Find the potential difference between A & C.

Text Solution

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The line joining B to C is perpendicular to electric field

So potential of B= potential of C
i.e., `V_(B)=V_(C)`
Distance difference between A & C `=ExxAB=5xx10^(3)xx(4xx10^(-2))`
=200 volt.
`AC^(2)=AB^(2)+B^(2)`
`AB^(2)=AC^(2)-BC^(2)`
`=25-9=16`
`AB=4cm`
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