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An electric dipole of length 4 cm, when ...

An electric dipole of length 4 cm, when placed with its axis electric field, experiences a torque of `4sqrt(3)Nm`. Calculate the potential energy of the dipole, if it has charge `+-8C`.

Text Solution

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Length `l=2a= 4cm 4xx 10^(-2)m`
Angle `theta=60^(@)`
Charge `Q=8xx10^(-9)C`
We know, that `tau= p E sin theta` [ where `p=Qxx2a]`
`tau=(Qxx2a) E sin theta`
`E=(del)/(Qx(2a) sin theta)`
`=(4sqrt(3))/(8xx10^(-9)xx4xx10^(-2)xx sin 60^(@))`
`:.` Potential energy `U=-p E cos theta`
`=-Q(2a)xxE cos theta`
`=-8xx10^(-9)xx4xx10^(-2)xx(4 sqrt(3)xxcos 60^(@))/(8xx10^(-9)xx4xx10^(-2)xxsin 60^(@))`
`U=(-4sqrt(3))/(sqrt(3))=-4J`
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