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Two insulated charge copper sphere A and...

Two insulated charge copper sphere A and B have their centres separated by a distance of 50 cm.
What is the force of repulsion, if each sphere is charged double the above amonunt and the distance between them is halved?

Text Solution

Verified by Experts

Now if `q_(1),q_(2)` are doubled and r. is halved then F becomes 16 times.
i.e., New force of
repulsion, `F.=16xx(1)/(4piepsi_(0))(q_(1)q_(2))/(r^(2))`
F.=16F
`=16xx1.521510^(-2)`
F.=0.24N
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Knowledge Check

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