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A parallel plate capacitor of capacitnac...

A parallel plate capacitor of capacitnace C is charge to a potential V. It is connected to another uncharged capactior having the same capacitance find the ratio of the energy stored in the constance to that stored initially in the single capacitor.

Text Solution

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Energy stored in the capacitor `=(1)/(2)CV^(2)=(q^(2))/(2C)`
Net capacitors of the parallel combination (when capacitors are connected to getter) =C+C=2C
Since the total charge Q remains same initial energy.
`U_(i)=(q^(2))/(2C)`
Final energy `U_(f)=(q^(2))/(2(2C))`
`(U_(f))/(U_(i))=1:2`
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