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If (a)/(b) = (c )/(d ) = (e )/(f) = (3)/...

If `(a)/(b) = (c )/(d ) = (e )/(f) = (3)/(4)`, what is the value of `(a+c +e )/( b+d +f)`?

A

a) `9//16`

B

b) `3//4`

C

c) `2//3 `

D

d) `4//5`

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The correct Answer is:
To solve the problem, we start with the given ratios: \[ \frac{a}{b} = \frac{c}{d} = \frac{e}{f} = \frac{3}{4} \] ### Step 1: Express variables in terms of a common variable From the ratios, we can express \(a\), \(c\), and \(e\) in terms of a common variable \(x\): - From \(\frac{a}{b} = \frac{3}{4}\), we can write: \[ a = 3x \quad \text{and} \quad b = 4x \] - From \(\frac{c}{d} = \frac{3}{4}\), we can write: \[ c = 3y \quad \text{and} \quad d = 4y \] - From \(\frac{e}{f} = \frac{3}{4}\), we can write: \[ e = 3z \quad \text{and} \quad f = 4z \] ### Step 2: Set the common variable Since all ratios are equal, we can set \(x = y = z\). Therefore, we can express all variables in terms of \(x\): - \(a = 3x\) - \(b = 4x\) - \(c = 3x\) - \(d = 4x\) - \(e = 3x\) - \(f = 4x\) ### Step 3: Calculate the numerator and denominator Now we need to find the value of \(\frac{a+c+e}{b+d+f}\): - The numerator: \[ a + c + e = 3x + 3x + 3x = 9x \] - The denominator: \[ b + d + f = 4x + 4x + 4x = 12x \] ### Step 4: Form the final expression Now we can substitute the values of the numerator and denominator into the fraction: \[ \frac{a+c+e}{b+d+f} = \frac{9x}{12x} \] ### Step 5: Simplify the expression We can simplify this fraction by canceling \(x\): \[ \frac{9x}{12x} = \frac{9}{12} = \frac{3}{4} \] ### Final Answer Thus, the value of \(\frac{a+c+e}{b+d+f}\) is: \[ \frac{3}{4} \]
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SSC SELECTION POST-SSC PREVIOUS YEAR PAPER HSC LEVEL (15 OCT 2019)-Section : Quantitative Aptitude Basic Arithmetic Skill
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