What would be the number in units place of the following expression: `182 xx 98 xx 971 xx 866`

Options

A. 6
B. 2
C. 4
D. 1

Answer

To find the number in the units place of the expression \(182 \times 98 \times 971 \times 866\), we can follow these steps:

### Step 1: Identify the units digits of each number
- The units digit of \(182\) is \(2\).
- The units digit of \(98\) is \(8\).
- The units digit of \(971\) is \(1\).
- The units digit of \(866\) is \(6\).

### Step 2: Multiply the units digits together
Now, we will multiply the units digits we identified:
\[ 2 \times 8 \times 1 \times 6 \]

### Step 3: Calculate the product step by step
1. First, multiply \(2\) and \(8\):
\[ 2 \times 8 = 16 \]
The units digit of \(16\) is \(6\).

2. Next, multiply the result by \(1\):
\[ 6 \times 1 = 6 \]
The units digit remains \(6\).

3. Finally, multiply by \(6\):
\[ 6 \times 6 = 36 \]
The units digit of \(36\) is \(6\).

### Conclusion
The units digit of the entire expression \(182 \times 98 \times 971 \times 866\) is \(6\).

### Final Answer
The number in the units place of the expression is **6**.

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