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The moles of O(2) required for reacting ...

The moles of `O_(2)` required for reacting with 6.8 ammonia
`(… NH_(3) + … O_(2) to … NO + … H_(2)O)` is

A

5

B

2.5

C

1

D

0.5

Text Solution

Verified by Experts

The correct Answer is:
D
The balanced equation is `4NH_(3) + 5O_(2) to 4NO+ 6H_(2)`
From the equation , `4 xx 17` of `NH_(2)` require
`O_(2) = 5 mol`
6.9 g of `NH_(3)` require `O_(2)`
= `(5 xx 6.8)/(4 xx 17) = 0.5 mol`
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