12 litre of `H_(2)` and 11.2 litre of `Cl_(2)` are mixed and exploded. The composition by volume of mixture is-

Options

A. 24 L HCI
B. `0.8 L CI_(2)` and 20.8 L HCI
C. 0.8 L `H_(2) and 22.4 L HCI`
D. 22.4 L HCI

Answer

C

Explanation

`H_(2) + CI_(2) to 2HCI`
Here, 11.2 L of `CI_(2)` is limiting agent.
Therefore, 11.2 L of `CI_(2)` will consume 11.2 L of `H_(2)` and produce 22.4 of HCI.
The amount of `H_(2)` left
= 12 - 11.2 = 0.8 L