If 2.0 g of the hydrogen on burning in 16.0 g of oxygen forms 18.0 g of water then which of the following laws is applicable?

Options

A. Law of conservation of mass
B. Law of constant compositions
C. Law of multiple proportions
D. Law of reciprocal proportions

Explanation

To solve the question regarding which law is applicable when 2.0 g of hydrogen burns in 16.0 g of oxygen to form 18.0 g of water, we will analyze the situation step by step.

### Step-by-Step Solution:

1. **Identify the Reactants and Products**:
- Reactants: Hydrogen (H₂) and Oxygen (O₂)
- Products: Water (H₂O)

2. **Determine the Mass of Reactants**:
- Mass of Hydrogen = 2.0 g
- Mass of Oxygen = 16.0 g
- Total mass of reactants = Mass of Hydrogen + Mass of Oxygen
- Total mass of reactants = 2.0 g + 16.0 g = 18.0 g

3. **Determine the Mass of Products**:
- Mass of Water produced = 18.0 g

4. **Apply the Law of Conservation of Mass**:
- According to the Law of Conservation of Mass, the total mass of the reactants must equal the total mass of the products.
- Here, the total mass of reactants (18.0 g) is equal to the total mass of products (18.0 g).

5. **Conclusion**:
- Since the mass of the reactants equals the mass of the products, the applicable law in this scenario is the **Law of Conservation of Mass**.

### Final Answer:
The applicable law is the **Law of Conservation of Mass**.

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