Sparking is produced in a mixture 20 mL `O_(2)` , and 20 mL CO, the volume of the gaseous mixture obtained will be

Options

A. 15 ml
B. 30 mL
C. 40 mL
D. 45 mL

Explanation

To solve the problem, we need to analyze the reaction between oxygen (O₂) and carbon monoxide (CO) and determine the volume of the gaseous mixture produced after the reaction.

### Step-by-Step Solution:

**Step 1: Identify the Reaction**
The reaction between oxygen and carbon monoxide can be represented as follows:
\[ 2 \text{CO} + \text{O}_2 \rightarrow 2 \text{CO}_2 \]
This means that two volumes of carbon monoxide react with one volume of oxygen to produce two volumes of carbon dioxide.

**Step 2: Determine the Initial Volumes**
We are given:
- Volume of O₂ = 20 mL
- Volume of CO = 20 mL

**Step 3: Calculate the Limiting Reactant**
From the balanced equation, we see that 2 volumes of CO react with 1 volume of O₂. Therefore, for 20 mL of CO, we need:
\[ \text{Required O}_2 = \frac{20 \text{ mL CO}}{2} = 10 \text{ mL O}_2 \]
Since we have 20 mL of O₂ available, O₂ is in excess, and CO is the limiting reactant.

**Step 4: Calculate the Volume of Products Formed**
According to the reaction, 2 volumes of CO produce 2 volumes of CO₂. Therefore, 20 mL of CO will produce:
\[ \text{Volume of CO}_2 = 20 \text{ mL CO} \]
Thus, 20 mL of CO will produce 20 mL of CO₂.

**Step 5: Calculate the Remaining Volume of O₂**
Since we used 10 mL of O₂ to react with 20 mL of CO, the remaining volume of O₂ is:
\[ \text{Remaining O}_2 = 20 \text{ mL} - 10 \text{ mL} = 10 \text{ mL} \]

**Step 6: Calculate the Total Volume of the Gaseous Mixture**
After the reaction, we have:
- 20 mL of CO₂ produced
- 10 mL of unreacted O₂ remaining

Thus, the total volume of the gaseous mixture is:
\[ \text{Total Volume} = \text{Volume of CO}_2 + \text{Remaining O}_2 = 20 \text{ mL} + 10 \text{ mL} = 30 \text{ mL} \]

### Final Answer:
The volume of the gaseous mixture obtained will be **30 mL**.

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