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An atom has 7 electrons in its M-shell a...

An atom has 7 electrons in its M-shell and contains 18 neutrons in its nucleus .What is its mass number ?

A

25

B

27

C

35

D

43

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The correct Answer is:
To find the mass number of the atom, we can follow these steps: ### Step 1: Understand the relationship between protons, neutrons, and mass number The mass number (A) of an atom is calculated using the formula: \[ A = \text{Number of protons} + \text{Number of neutrons} \] ### Step 2: Determine the number of protons We know that the number of electrons in a neutral atom is equal to the number of protons. The problem states that there are 7 electrons in the M-shell. However, we must consider the total number of electrons in all shells. - K shell can hold a maximum of 2 electrons. - L shell can hold a maximum of 8 electrons. - M shell has 7 electrons as given. Thus, the total number of electrons is: \[ \text{Total electrons} = 2 (\text{K shell}) + 8 (\text{L shell}) + 7 (\text{M shell}) = 17 \] Since the number of protons is equal to the number of electrons in a neutral atom: \[ \text{Number of protons} = 17 \] ### Step 3: Use the number of neutrons The problem states that there are 18 neutrons in the nucleus. ### Step 4: Calculate the mass number Now we can substitute the values into the mass number formula: \[ A = \text{Number of protons} + \text{Number of neutrons} \] \[ A = 17 + 18 \] \[ A = 35 \] ### Conclusion The mass number of the atom is 35. ### Final Answer The correct option is C: 35. ---

To find the mass number of the atom, we can follow these steps: ### Step 1: Understand the relationship between protons, neutrons, and mass number The mass number (A) of an atom is calculated using the formula: \[ A = \text{Number of protons} + \text{Number of neutrons} \] ### Step 2: Determine the number of protons We know that the number of electrons in a neutral atom is equal to the number of protons. The problem states that there are 7 electrons in the M-shell. However, we must consider the total number of electrons in all shells. ...
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