An element 'Y' has a ground state configuration 2,8,8 the type of bond that exists between the atoms of 'Y' is

Options

A. ionic
B. covalent
C. metallic
D. vander Waals bond

Explanation

To determine the type of bond that exists between the atoms of element 'Y' with a ground state configuration of 2,8,8, we can follow these steps:

### Step 1: Analyze the Electronic Configuration
The electronic configuration of element 'Y' is given as 2,8,8. This means that:
- The first shell has 2 electrons.
- The second shell has 8 electrons.
- The third shell has 8 electrons.

### Step 2: Identify the Valence Electrons
The outermost shell (the third shell) contains 8 electrons. This indicates that the outermost shell is fully filled.

### Step 3: Determine the Type of Bond
1. **Ionic Bond**: In ionic bonding, electrons are transferred from one atom to another. However, since element 'Y' has a fully filled outer shell, it is unlikely to lose or gain electrons.

2. **Covalent Bond**: In covalent bonding, atoms share electrons. Again, because the outer shell is fully filled, there is no need for sharing electrons.

3. **Metallic Bond**: In metallic bonding, electrons are delocalized and shared among a lattice of metal atoms. While this could be a possibility, the configuration suggests a different type of bond.

4. **Van der Waals Bond**: This type of bond is characterized by weak attractions between molecules or atoms. Since element 'Y' has a fully filled outer shell, it is more likely to exhibit weak interactions rather than strong ionic or covalent bonds.

### Conclusion
Based on the analysis, the type of bond that exists between the atoms of element 'Y' is a **Van der Waals bond**.

### Final Answer:
The type of bond that exists between the atoms of 'Y' is **Van der Waals bond** (Option D).

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