Which of the following is soluable in water

Options

A. `CS_(4)`
B. `C_(2)H_(5)OH`
C. `C Cl_(4)`
D. `CHCl_(3)`

Answer

To determine which of the given compounds is soluble in water, we will analyze each option based on their chemical properties and interactions with water.

### Step-by-Step Solution:

1. **Identify the Compounds**:
We need to analyze the solubility of the following compounds:
- CS4 (Carbon disulfide)
- Ethanol (C2H5OH)
- CCl4 (Carbon tetrachloride)
- CHCl3 (Chloroform)

2. **Analyze CS4 (Carbon Disulfide)**:
- CS4 is known to be slightly soluble in water. However, its solubility is very low compared to other compounds.
- **Conclusion**: CS4 is not significantly soluble in water.

3. **Analyze Ethanol (C2H5OH)**:
- Ethanol contains a hydroxyl (OH) group, which can form hydrogen bonds with water molecules.
- This ability to form hydrogen bonds makes ethanol highly soluble in water.
- **Conclusion**: Ethanol is soluble in water.

4. **Analyze CCl4 (Carbon Tetrachloride)**:
- CCl4 is a non-polar molecule. The symmetrical arrangement of its bonds results in a cancellation of dipole moments, making it non-polar.
- Non-polar substances do not interact well with polar solvents like water, leading to very low solubility.
- **Conclusion**: CCl4 is not soluble in water.

5. **Analyze CHCl3 (Chloroform)**:
- CHCl3 is a polar molecule due to the presence of chlorine atoms, which create a dipole moment. However, it does not form strong hydrogen bonds with water.
- The lack of significant interaction with water results in lower solubility compared to more polar compounds.
- **Conclusion**: CHCl3 has limited solubility in water.

### Final Conclusion:
Among the given compounds, **Ethanol (C2H5OH)** is the only compound that is soluble in water.

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