An element has the electronic configuration `1s^(2),2s^(2),2p^(6),3s^(2),3p^(2)` The number of valency electrons will be

Options

A. 2
B. 3
C. 4
D. 5

Explanation

To determine the number of valency electrons for the element with the electronic configuration `1s^(2), 2s^(2), 2p^(6), 3s^(2), 3p^(2)`, we can follow these steps:

### Step 1: Identify the total number of electrons
The electronic configuration provided is:
- `1s^(2)` contributes 2 electrons
- `2s^(2)` contributes 2 electrons
- `2p^(6)` contributes 6 electrons
- `3s^(2)` contributes 2 electrons
- `3p^(2)` contributes 2 electrons

Now, let's add these up:
\[ 2 (from \, 1s) + 2 (from \, 2s) + 6 (from \, 2p) + 2 (from \, 3s) + 2 (from \, 3p) = 14 \, electrons \]

### Step 2: Determine the atomic number
The total number of electrons is equal to the atomic number of the element. Therefore, the atomic number is 14.

### Step 3: Identify the element
The element with atomic number 14 is Silicon (Si).

### Step 4: Determine the valence electrons
Valence electrons are the electrons in the outermost shell. For Silicon:
- The outermost shell is the third shell (n=3).
- The configuration for the outermost shell is `3s^(2)` and `3p^(2)`.
- The total number of valence electrons is:
\[ 2 (from \, 3s) + 2 (from \, 3p) = 4 \, valence \, electrons \]

### Conclusion
The number of valency electrons for the element with the given electronic configuration is **4**.