The number of sulphur atoms in its 40 g is

Options

A. `40 xx 6.023 xx 10^23
B. `32 xx 6.023 xx 10^23`
C. `(40 xx 6 xx 10^23)/(32)`
D. `(32 xx 6 xx 10^23)/(40)`

Explanation

To find the number of sulfur atoms in 40 g of sulfur, we can follow these steps:

### Step 1: Identify the given data
- Mass of sulfur (m) = 40 g
- Molar mass of sulfur (M) = 32 g/mol

### Step 2: Use the formula to find the number of moles
The number of moles (n) of sulfur can be calculated using the formula:
\[ n = \frac{\text{mass of element (g)}}{\text{molar mass (g/mol)}} \]
Substituting the values:
\[ n = \frac{40 \, \text{g}}{32 \, \text{g/mol}} = 1.25 \, \text{mol} \]

### Step 3: Calculate the number of atoms
To find the number of atoms, we use Avogadro's number, which is \(6.022 \times 10^{23}\) atoms/mol. The number of atoms (N) can be calculated using the formula:
\[ N = n \times N_A \]
where \(N_A\) is Avogadro's number. Substituting the values:
\[ N = 1.25 \, \text{mol} \times 6.022 \times 10^{23} \, \text{atoms/mol} \]
Calculating this gives:
\[ N \approx 7.53 \times 10^{23} \, \text{atoms} \]

### Final Answer
The number of sulfur atoms in 40 g of sulfur is approximately \(7.53 \times 10^{23}\) atoms.

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