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The periodic decimal 0.272727... = 0.bar...

The periodic decimal `0.272727... = 0.bar(27)` is the rational number

A

`3/11`

B

`1/7`

C

`2/7`

D

`1/11`

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AI Generated Solution

The correct Answer is:
To convert the periodic decimal \(0.272727...\) (which can be denoted as \(0.\overline{27}\)) into a rational number, we can follow these steps: ### Step 1: Let \(x\) equal the periodic decimal. Let: \[ x = 0.272727... \] ### Step 2: Multiply \(x\) by a power of 10 to shift the decimal point. Since the repeating part "27" has 2 digits, multiply \(x\) by \(100\): \[ 100x = 27.272727... \] ### Step 3: Set up an equation to eliminate the repeating part. Now, we have two equations: 1. \(x = 0.272727...\) 2. \(100x = 27.272727...\) Subtract the first equation from the second: \[ 100x - x = 27.272727... - 0.272727... \] This simplifies to: \[ 99x = 27 \] ### Step 4: Solve for \(x\). Now, divide both sides by \(99\): \[ x = \frac{27}{99} \] ### Step 5: Simplify the fraction. To simplify \(\frac{27}{99}\), we can divide both the numerator and the denominator by their greatest common divisor, which is \(9\): \[ x = \frac{27 \div 9}{99 \div 9} = \frac{3}{11} \] ### Conclusion Thus, the periodic decimal \(0.272727...\) can be expressed as the rational number: \[ \frac{3}{11} \]
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