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The HCF of two polynomials is x+ 3 and t...

The HCF of two polynomials is x+ 3 and their LCM is `x^(3) - 7x + 6`. If one of the polynomials is `x^(2) + 2x - 3`. Then, the other polynomial is

A

`x^(2) - x + 6`

B

`x^(2) + x - 6`

C

`x^(2) + x + 2`

D

`x^(2) + x + 3`

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The correct Answer is:
To find the other polynomial given the HCF and LCM of two polynomials, we can use the relationship between HCF, LCM, and the polynomials themselves. The relationship states that: \[ \text{HCF}(P, Q) \times \text{LCM}(P, Q) = P \times Q \] Where \( P \) and \( Q \) are the two polynomials. ### Step-by-Step Solution: 1. **Identify the Given Values:** - HCF = \( x + 3 \) - LCM = \( x^3 - 7x + 6 \) - One polynomial \( P = x^2 + 2x - 3 \) 2. **Apply the Relationship:** Using the relationship mentioned above, we can express the other polynomial \( Q \) as follows: \[ Q = \frac{\text{HCF} \times \text{LCM}}{P} \] 3. **Calculate the Product of HCF and LCM:** Substitute the values of HCF and LCM into the equation: \[ \text{HCF} \times \text{LCM} = (x + 3)(x^3 - 7x + 6) \] 4. **Expand the Product:** We need to expand \( (x + 3)(x^3 - 7x + 6) \): \[ = x(x^3 - 7x + 6) + 3(x^3 - 7x + 6) \] \[ = x^4 - 7x^2 + 6x + 3x^3 - 21x + 18 \] \[ = x^4 + 3x^3 - 7x^2 - 15x + 18 \] 5. **Substitute \( P \) into the Equation:** Now we need to divide the expanded product by \( P \): \[ Q = \frac{x^4 + 3x^3 - 7x^2 - 15x + 18}{x^2 + 2x - 3} \] 6. **Perform Polynomial Long Division:** We will perform polynomial long division of \( x^4 + 3x^3 - 7x^2 - 15x + 18 \) by \( x^2 + 2x - 3 \). - Divide the leading term: \( x^4 \div x^2 = x^2 \) - Multiply \( x^2 \) by \( x^2 + 2x - 3 \) and subtract: \[ x^4 + 2x^3 - 3x^2 \] - Subtract: \[ (3x^3 - 2x^3) + (-7x^2 + 3x^2) - 15x + 18 = x^3 - 4x^2 - 15x + 18 \] - Repeat the process: - Divide \( x^3 \div x^2 = x \) - Multiply and subtract: \[ x^3 + 2x^2 - 3x \] - Resulting in: \[ (-4x^2 - 2x + 18) \] - Finally: - Divide \( -4x^2 \div x^2 = -4 \) - Multiply and subtract: \[ -4x^2 - 8x + 12 \] - Resulting in: \[ (-15x + 8x + 18 - 12) = -7x + 6 \] - The final result of the division is: \[ Q = x^2 + x - 4 + \frac{-7x + 6}{x^2 + 2x - 3} \] 7. **Final Result:** The other polynomial \( Q \) is: \[ Q = x^2 - 4 \]
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