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The LCM of 2(a^(2)-b^(2)), 3(a^(3) - b^(...

The LCM of `2(a^(2)-b^(2)), 3(a^(3) - b^(3)), 4(a^(4) - b^(4))` is

A

`6(a-b)(a+b)(a^(2) + b^(2))`

B

`12(a^(4)-b^(4)) (a^(2) + ab + b^(2))`

C

`a^(3) - b^(3)`

D

`12(a^(4) - b^(4))`

Text Solution

AI Generated Solution

The correct Answer is:
To find the LCM of the expressions \(2(a^2 - b^2)\), \(3(a^3 - b^3)\), and \(4(a^4 - b^4)\), we will follow these steps: ### Step 1: Factor each expression 1. **Factor \(2(a^2 - b^2)\)**: \[ a^2 - b^2 = (a + b)(a - b) \] Thus, \[ 2(a^2 - b^2) = 2(a + b)(a - b) \] 2. **Factor \(3(a^3 - b^3)\)**: \[ a^3 - b^3 = (a - b)(a^2 + ab + b^2) \] Thus, \[ 3(a^3 - b^3) = 3(a - b)(a^2 + ab + b^2) \] 3. **Factor \(4(a^4 - b^4)\)**: \[ a^4 - b^4 = (a^2 - b^2)(a^2 + b^2) = (a + b)(a - b)(a^2 + b^2) \] Thus, \[ 4(a^4 - b^4) = 4(a + b)(a - b)(a^2 + b^2) \] ### Step 2: Identify the LCM Now we have: - \(2(a + b)(a - b)\) - \(3(a - b)(a^2 + ab + b^2)\) - \(4(a + b)(a - b)(a^2 + b^2)\) To find the LCM, we take the highest power of each factor present in any of the expressions: - The highest coefficient is \(4\) (from \(4(a^4 - b^4)\)). - The factors are: - \(a + b\) (from \(4(a + b)(a - b)(a^2 + b^2)\)) - \(a - b\) (common in all three) - \(a^2 + ab + b^2\) (from \(3(a^3 - b^3)\)) - \(a^2 + b^2\) (from \(4(a^4 - b^4)\)) ### Step 3: Combine the factors Thus, the LCM is: \[ LCM = 4(a + b)(a - b)(a^2 + ab + b^2)(a^2 + b^2) \] ### Final Result The LCM of \(2(a^2 - b^2)\), \(3(a^3 - b^3)\), and \(4(a^4 - b^4)\) is: \[ 4(a + b)(a - b)(a^2 + ab + b^2)(a^2 + b^2) \] ---
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the value of the determinant |{:((a_(1)-b_(1))^(2),,(a_(1)-b_(2))^(2),,(a_(1)-b_(3))^(2),,(a_(1)-b_(4))^(2)),((a_(2)-b_(1))^(2),,(a_(2)-b_(2))^(2) ,,(a_(2)-b_(3))^(2),,(a_(3)-b_(4))^(2)),((a_(3)-b_(1))^(2),,(a_(3)-b_(2))^(2),,(a_(3)-b_(3))^(2),,(a_(3)-b_(4))^(2)),((a_(4)-b_(1))^(2),,(a_(4)-b_(2))^(2),,(a_(4)-b_(3))^(2),,(a_(4)-b_(4))^(2)):}| is

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