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A metal pipe in 77 cm long. If the inner...

A metal pipe in 77 cm long. If the inner diameter ofa cross section is 4 cm and the outer diameter being 4.4 cm. Then, its outer curved surface area is

A

1164.8 `cm^2`

B

1440.8 `cm^2`

C

123.8 `cm^2`

D

1064.8 `cm^2`

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The correct Answer is:
To find the outer curved surface area of the metal pipe, we can follow these steps: ### Step 1: Identify the given dimensions - Length of the pipe (h) = 77 cm - Outer diameter (D) = 4.4 cm ### Step 2: Calculate the outer radius (r) The radius is half of the diameter: \[ r = \frac{D}{2} = \frac{4.4 \, \text{cm}}{2} = 2.2 \, \text{cm} \] ### Step 3: Use the formula for the curved surface area of a cylinder The formula for the curved surface area (CSA) of a cylinder is: \[ \text{CSA} = 2 \pi r h \] ### Step 4: Substitute the values into the formula Using \( \pi \approx \frac{22}{7} \): \[ \text{CSA} = 2 \times \frac{22}{7} \times 2.2 \, \text{cm} \times 77 \, \text{cm} \] ### Step 5: Simplify the expression Calculate \( 2 \times 2.2 = 4.4 \): \[ \text{CSA} = \frac{22}{7} \times 4.4 \times 77 \] ### Step 6: Calculate \( 4.4 \times 77 \) \[ 4.4 \times 77 = 338.8 \] ### Step 7: Substitute back into the equation Now we have: \[ \text{CSA} = \frac{22}{7} \times 338.8 \] ### Step 8: Multiply and simplify Calculating \( 22 \times 338.8 = 7453.6 \): \[ \text{CSA} = \frac{7453.6}{7} \] ### Step 9: Final calculation Now divide: \[ \text{CSA} = 1064.8 \, \text{cm}^2 \] Thus, the outer curved surface area of the metal pipe is **1064.8 cm²**. ---
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