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If sqrt2 sin (60^(@) - theta) = 1, then...

If ` sqrt2 sin (60^(@) - theta) = 1,` then the value of ` theta ` is

A

`20^(@)`

B

`30^(@)`

C

`15 ^(@)`

D

None of these

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The correct Answer is:
To solve the equation \( \sqrt{2} \sin(60^\circ - \theta) = 1 \), we will follow these steps: ### Step 1: Isolate the sine function We start with the given equation: \[ \sqrt{2} \sin(60^\circ - \theta) = 1 \] To isolate the sine function, we divide both sides by \( \sqrt{2} \): \[ \sin(60^\circ - \theta) = \frac{1}{\sqrt{2}} \] ### Step 2: Recognize the sine value We know that \( \frac{1}{\sqrt{2}} \) is equal to \( \sin(45^\circ) \). Therefore, we can rewrite the equation as: \[ \sin(60^\circ - \theta) = \sin(45^\circ) \] ### Step 3: Set up the angle equations Since the sine function is equal for angles that differ by \( n \cdot 180^\circ \) or are supplementary, we can set up the following equations: 1. \( 60^\circ - \theta = 45^\circ + n \cdot 180^\circ \) 2. \( 60^\circ - \theta = 180^\circ - 45^\circ + n \cdot 180^\circ \) For simplicity, we will consider \( n = 0 \) first. ### Step 4: Solve the first equation From the first equation: \[ 60^\circ - \theta = 45^\circ \] Rearranging gives: \[ \theta = 60^\circ - 45^\circ = 15^\circ \] ### Step 5: Solve the second equation Now, let's solve the second equation: \[ 60^\circ - \theta = 135^\circ \] Rearranging gives: \[ \theta = 60^\circ - 135^\circ = -75^\circ \] Since \( \theta \) must be a positive angle in this context, we discard this solution. ### Conclusion Thus, the only valid solution is: \[ \theta = 15^\circ \]
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