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The value of (cos (90^(@) + A) sec ( 3...

The value of
`(cos (90^(@) + A) sec ( 360^(@) - A) tan ( 180^(@) - A))/( sec (A - 720^(@)) sin ( 54 0 ^(@) + A) cot (A - 90^(@)))` is

A

0

B

1

C

`oo`

D

None of these

Text Solution

AI Generated Solution

The correct Answer is:
To solve the expression \[ \frac{\cos(90^\circ + A) \sec(360^\circ - A) \tan(180^\circ - A)}{\sec(A - 720^\circ) \sin(540^\circ + A) \cot(A - 90^\circ)} \] we will simplify each trigonometric function step by step. ### Step 1: Simplifying \(\cos(90^\circ + A)\) Using the identity \(\cos(90^\circ + \theta) = -\sin(\theta)\): \[ \cos(90^\circ + A) = -\sin(A) \] ### Step 2: Simplifying \(\sec(360^\circ - A)\) Using the identity \(\sec(360^\circ - \theta) = \sec(\theta)\): \[ \sec(360^\circ - A) = \sec(A) \] ### Step 3: Simplifying \(\tan(180^\circ - A)\) Using the identity \(\tan(180^\circ - \theta) = -\tan(\theta)\): \[ \tan(180^\circ - A) = -\tan(A) \] ### Step 4: Putting it all together in the numerator Now substituting these results into the numerator: \[ \text{Numerator} = (-\sin(A)) \cdot \sec(A) \cdot (-\tan(A)) = \sin(A) \sec(A) \tan(A) \] ### Step 5: Simplifying \(\sec(A - 720^\circ)\) Using the identity \(\sec(\theta - 360^\circ) = \sec(\theta)\): \[ \sec(A - 720^\circ) = \sec(A) \] ### Step 6: Simplifying \(\sin(540^\circ + A)\) Using the identity \(\sin(540^\circ + \theta) = -\sin(\theta)\): \[ \sin(540^\circ + A) = -\sin(A) \] ### Step 7: Simplifying \(\cot(A - 90^\circ)\) Using the identity \(\cot(\theta - 90^\circ) = -\tan(\theta)\): \[ \cot(A - 90^\circ) = -\tan(A) \] ### Step 8: Putting it all together in the denominator Now substituting these results into the denominator: \[ \text{Denominator} = \sec(A) \cdot (-\sin(A)) \cdot (-\tan(A)) = \sec(A) \sin(A) \tan(A) \] ### Step 9: Final simplification Now we have: \[ \frac{\sin(A) \sec(A) \tan(A)}{\sec(A) \sin(A) \tan(A)} \] Both the numerator and denominator are equal, thus simplifying to: \[ \frac{\sin(A) \sec(A) \tan(A)}{\sin(A) \sec(A) \tan(A)} = 1 \] ### Final Answer The value of the expression is: \[ \boxed{1} \]
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