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The velocity-time relation of a body sta...

The velocity-time relation of a body starting from rest is given by `v= k^2t^(3/2)`, where `k=sqrt2 m^(1/2)/s^(5/4)`. The distance traversed in 4 second is

A

8 m

B

64 m

C

4 m

D

36 m

Text Solution

Verified by Experts

The correct Answer is:
D
Distance travelled in 5s
`D_(5) u (5)+(1)/(2) a (5)^(2)`
Distance travelled in 4s
`D_(4)=u (4) +(1)/(2) a(4)^(2)`
`D_(5)-D_(4)=u+(1)/(2) axx9`
`therefore` Distance travelled in 5th second
`=(1)/(2) a xx9=(1)/(2)xx8xx9=36 m`
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