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Two unit vectors under vector multiplic...

Two unit vectors under vector multiplication have magnitude one if angle between them is of

A

`45^(@)`

B

`90^(@)`

C

`60^(@)`

D

`120^(@)`

Text Solution

AI Generated Solution

The correct Answer is:
To solve the problem, we need to determine the angle between two unit vectors when their vector multiplication (cross product) has a magnitude of 1. Here’s the step-by-step solution: ### Step 1: Understand the Definition of Unit Vectors We are given two unit vectors, which means that the magnitudes of both vectors \( \mathbf{A} \) and \( \mathbf{B} \) are equal to 1: \[ |\mathbf{A}| = 1 \quad \text{and} \quad |\mathbf{B}| = 1 \] **Hint:** Remember that a unit vector has a magnitude of 1. ### Step 2: Recall the Formula for Vector Cross Product The magnitude of the cross product of two vectors \( \mathbf{A} \) and \( \mathbf{B} \) is given by the formula: \[ |\mathbf{A} \times \mathbf{B}| = |\mathbf{A}| \cdot |\mathbf{B}| \cdot \sin(\theta) \] where \( \theta \) is the angle between the two vectors. **Hint:** The cross product involves both the magnitudes of the vectors and the sine of the angle between them. ### Step 3: Substitute the Magnitudes into the Formula Since both vectors are unit vectors, we can substitute their magnitudes into the equation: \[ |\mathbf{A} \times \mathbf{B}| = 1 \cdot 1 \cdot \sin(\theta) = \sin(\theta) \] **Hint:** Simplifying the equation helps to focus on the sine function. ### Step 4: Set Up the Equation According to the problem, the magnitude of the cross product is given as 1: \[ \sin(\theta) = 1 \] **Hint:** This equation tells us about the relationship between the sine of the angle and its maximum value. ### Step 5: Solve for the Angle The sine function equals 1 at a specific angle: \[ \sin(\theta) = 1 \implies \theta = 90^\circ \] **Hint:** Recall the values of sine for common angles to find the solution. ### Conclusion Thus, the angle between the two unit vectors when their vector multiplication has a magnitude of 1 is: \[ \theta = 90^\circ \] **Final Answer:** The angle between the two unit vectors is \( 90^\circ \). ---

To solve the problem, we need to determine the angle between two unit vectors when their vector multiplication (cross product) has a magnitude of 1. Here’s the step-by-step solution: ### Step 1: Understand the Definition of Unit Vectors We are given two unit vectors, which means that the magnitudes of both vectors \( \mathbf{A} \) and \( \mathbf{B} \) are equal to 1: \[ |\mathbf{A}| = 1 \quad \text{and} \quad |\mathbf{B}| = 1 \] ...
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