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The square of resultant of two equal for...

The square of resultant of two equal forces is three times their product. Angle between the force is

A

`pi`

B

`pi//2`

C

`pi//3`

D

`pi//4`

Text Solution

Verified by Experts

The correct Answer is:
C
By law of parallelogram of vectors,
`R^(2)=P^(2)+Q^(2)+2PQ cos theta`
Here `P =Q`
`R^(2)=3PQ`
`therefore 3PQ =P^(2)+P^(2)+2P^(2) cos theta`
`therefore 3P^(2)-2P^(2)=2P^(2) cos theta`
`therefore cos theta =1//2 rArr theta = 60^(@) =(pi)/(3)` radian
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