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A cannon of mass 150 kg shot a cannon ba...

A cannon of mass 150 kg shot a cannon ball of 1.5 kg which goes with a velocity of 60 m/s. The cannon will recoil with a speed o

A

10.5 m/s

B

6 m/s

C

0.6 m/s

D

None of these

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The correct Answer is:
To solve the problem of the cannon recoiling after firing a cannonball, we will use the principle of conservation of momentum. Here’s a step-by-step solution: ### Step 1: Understand the Problem We have a cannon of mass \( m_c = 150 \, \text{kg} \) and a cannonball of mass \( m_b = 1.5 \, \text{kg} \) that is shot with a velocity \( v_b = 60 \, \text{m/s} \). We need to find the recoil speed \( v_c \) of the cannon after firing. ### Step 2: Apply the Conservation of Momentum According to the law of conservation of momentum, the total momentum before the event (firing the cannonball) must equal the total momentum after the event. **Initial Momentum:** Since both the cannon and cannonball are at rest before firing, the initial momentum \( P_{\text{initial}} \) is: \[ P_{\text{initial}} = 0 \] **Final Momentum:** After the cannonball is fired, the momentum of the cannonball and the cannon must equal the initial momentum: \[ P_{\text{final}} = m_b \cdot v_b + m_c \cdot v_c \] Where: - \( m_b \) is the mass of the cannonball, - \( v_b \) is the velocity of the cannonball, - \( m_c \) is the mass of the cannon, - \( v_c \) is the recoil velocity of the cannon (which we need to find). ### Step 3: Set Up the Equation Since momentum is conserved: \[ P_{\text{initial}} = P_{\text{final}} \] This gives us: \[ 0 = m_b \cdot v_b + m_c \cdot v_c \] ### Step 4: Substitute the Known Values Substituting the known values into the equation: \[ 0 = (1.5 \, \text{kg}) \cdot (60 \, \text{m/s}) + (150 \, \text{kg}) \cdot v_c \] \[ 0 = 90 \, \text{kg m/s} + 150 \, \text{kg} \cdot v_c \] ### Step 5: Solve for \( v_c \) Rearranging the equation to solve for \( v_c \): \[ 150 \, v_c = -90 \] \[ v_c = \frac{-90}{150} \] \[ v_c = -0.6 \, \text{m/s} \] ### Step 6: Interpret the Result The negative sign indicates that the cannon recoils in the opposite direction to the cannonball. Thus, the speed of the cannon's recoil is \( 0.6 \, \text{m/s} \). ### Final Answer The recoil speed of the cannon is \( 0.6 \, \text{m/s} \) in the direction opposite to that of the cannonball. ---

To solve the problem of the cannon recoiling after firing a cannonball, we will use the principle of conservation of momentum. Here’s a step-by-step solution: ### Step 1: Understand the Problem We have a cannon of mass \( m_c = 150 \, \text{kg} \) and a cannonball of mass \( m_b = 1.5 \, \text{kg} \) that is shot with a velocity \( v_b = 60 \, \text{m/s} \). We need to find the recoil speed \( v_c \) of the cannon after firing. ### Step 2: Apply the Conservation of Momentum According to the law of conservation of momentum, the total momentum before the event (firing the cannonball) must equal the total momentum after the event. ...
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