A car is moving along a straight horizontal road with a speed `v_(0)` . If the coefficient of friction between the tyre and the road is mu, the shortest distance in which the car can be stopped is.

Options

A. `v ^(2) //2 mug`
B. `v//2 mu g`
C. `2v // mu ^(2) g`
D. `2v // mu g`

Answer

A

Explanation

As, `v ^(2) = u ^(2) + 2 as`
Here , `u = v , a = - mu g v = 0 , s = ? `
`0 = v ^(2) + 2 ( - mu g ) s implies s = (v ^(2))/( 2 mu g )`