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A mass of 1kg is hanged through a spring...

A mass of 1kg is hanged through a spring. The spring is stretched through 1cm. What is the energy stared in spring?

A

0.449J

B

0.049J

C

4.9J

D

49J

Text Solution

Verified by Experts

The correct Answer is:
B
Force `F= K .x`
`1 xx 9.8 = K xx 1 xx 10^(-2)`
`K= (9.8)/(10^(-2))= 980`
Potential energy conserved in the spring, `U = (1)/(2) Kx^(2) = (1)/(2) xx 980 xx 10^(-4)`
`=490 xx 10^(-4)= 0.049J`
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