A force of 10N is applied to a stationary mass of 25kg. The work done in the 1st second is given by

Options

A. 10J
B. 2J
C. 25J
D. 2.6J

Explanation

To solve the problem of calculating the work done on a stationary mass of 25 kg when a force of 10 N is applied for the first second, we can follow these steps:

### Step 1: Identify the given values
- Force (F) = 10 N
- Mass (m) = 25 kg
- Time (t) = 1 second

### Step 2: Calculate the acceleration
Using Newton's second law of motion, we can find the acceleration (a) using the formula:
\[ F = m \cdot a \]
Rearranging gives:
\[ a = \frac{F}{m} \]
Substituting the values:
\[ a = \frac{10 \, \text{N}}{25 \, \text{kg}} = 0.4 \, \text{m/s}^2 \]

### Step 3: Calculate the displacement
Since the object is initially stationary, the initial velocity (u) is 0. We can use the formula for displacement (s) under constant acceleration:
\[ s = u \cdot t + \frac{1}{2} a \cdot t^2 \]
Substituting the values:
\[ s = 0 \cdot 1 + \frac{1}{2} \cdot 0.4 \cdot (1)^2 \]
\[ s = 0 + \frac{1}{2} \cdot 0.4 \cdot 1 \]
\[ s = 0.2 \, \text{m} \]

### Step 4: Calculate the work done
The work done (W) is given by the formula:
\[ W = F \cdot s \cdot \cos(\theta) \]
Since the force is applied in the same direction as the displacement, \(\theta = 0\) degrees, and \(\cos(0) = 1\):
\[ W = F \cdot s \]
Substituting the values:
\[ W = 10 \, \text{N} \cdot 0.2 \, \text{m} \]
\[ W = 2 \, \text{J} \]

### Final Answer
The work done in the first second is **2 Joules**.

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