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A 400kg car attains a speed of 50m/s fro...

A 400kg car attains a speed of 50m/s from rest in 20s. The power developed in the engine will be

A

50W

B

0.5W

C

5kW

D

25kW

Text Solution

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The correct Answer is:
To solve the problem of finding the power developed in the engine of a car that accelerates from rest to a speed of 50 m/s in 20 seconds, we can follow these steps: ### Step 1: Calculate the Change in Kinetic Energy The formula for kinetic energy (KE) is given by: \[ KE = \frac{1}{2} m v^2 \] Where: - \( m \) is the mass of the car (400 kg) - \( v \) is the final velocity (50 m/s) First, we calculate the initial kinetic energy (when the car is at rest, \( v = 0 \)): \[ KE_{\text{initial}} = \frac{1}{2} \times 400 \times 0^2 = 0 \, \text{J} \] Next, we calculate the final kinetic energy: \[ KE_{\text{final}} = \frac{1}{2} \times 400 \times (50)^2 = \frac{1}{2} \times 400 \times 2500 = 500000 \, \text{J} \] Now, we find the change in kinetic energy: \[ \Delta KE = KE_{\text{final}} - KE_{\text{initial}} = 500000 \, \text{J} - 0 \, \text{J} = 500000 \, \text{J} \] ### Step 2: Calculate the Power Developed Power is defined as the work done per unit time. In this case, the work done is equal to the change in kinetic energy: \[ P = \frac{\text{Work}}{\text{Time}} = \frac{\Delta KE}{t} \] Where: - \( t \) is the time taken (20 s) Substituting the values: \[ P = \frac{500000 \, \text{J}}{20 \, \text{s}} = 25000 \, \text{W} \] ### Step 3: Convert Watts to Kilowatts To convert watts to kilowatts, we divide by 1000: \[ P = \frac{25000 \, \text{W}}{1000} = 25 \, \text{kW} \] ### Final Answer The power developed in the engine is **25 kW**. ---

To solve the problem of finding the power developed in the engine of a car that accelerates from rest to a speed of 50 m/s in 20 seconds, we can follow these steps: ### Step 1: Calculate the Change in Kinetic Energy The formula for kinetic energy (KE) is given by: \[ KE = \frac{1}{2} m v^2 \] Where: ...
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