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The molecular weight of a gas is 44. the...

The molecular weight of a gas is 44. the volume occupied by 2.2 g of this gas at `0^(@)C` and 2 atm pressure will be

A

0.56 L

B

1.2 L

C

2.4L

D

5.6 L

Text Solution

Verified by Experts

The correct Answer is:
A
Number of moles of gas `= (22)/(44) = (1)/(20)` mole
One mole of a gas occupies 22.4 L at NTP
pV = nRT
`rArr (p_(1)V_(1))/(p_(2)V_(2)) = (n_(1))/(n_(2)) = (n_(1))/(n_(2)) rArr V_(2) = (p_(1))/(p_(2)) xx (n_(1))/(n_(2))V_(1) = (22.4)/(20 xx 2)`
`rArr V_(2) = 0.56 L`
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