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When volume of system is increased two t...

When volume of system is increased two times and temperature is decreased half of its initial temperature, then pressure becomes ………….

A

2 times

B

4 times

C

`(1)/(4)` times

D

`(1)/(2)` times

Text Solution

Verified by Experts

The correct Answer is:
C

As, `pv = RT`
`rArr p_(1)V_(1) = RT_(1)` and `V_(2) = 2V_(1), T_(2) = (T_(1))/(2), p_(2) = ?`
`(p_(1)V_(1))/(p_(2)V_(2)) = (T_(1))/(T_(2)) rArr (p_(1))/(p_(2)).(V_(1))/(2V_(1)) = (2T_(1))/(T_(1))`
`rarr (p_(1))/(p_(2)) = 4`
`p_(2) = (p_(1))/(4)` = One-fourth of initial pressure.
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