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The kinetic energy of translation of 20g...

The kinetic energy of translation of 20gm of oxygen at `47^(@)C` is (molecular wt. of oxygen is 32 gm/mol and R=8.3 J/mol/K)

A

2490J

B

2390J

C

830 J

D

124.5J

Text Solution

Verified by Experts

The correct Answer is:
A
For 1 g gas, pV = RT
For 20 g `O_(2)`, pV `= 20RT = (20RT)/(32)`
`therefore K E = (3)/(2) xx 20 xx (R)/(32) xx T`
`= (3)/(2) xx 20 xx (83)/(32) xx 320 = 2490 J`
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