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Hot water cools from 60^@C to 50^@C in t...

Hot water cools from `60^@C` to `50^@C` in the first 10 min and to `42^@C` in the next 10 min. The temperature of the surrounding is

A

`10^(@)` C

B

`15^(@)` C

C

`20^(@)` C

D

`25^(@)` C

Text Solution

Verified by Experts

The correct Answer is:
A
By Newton.s law of cooling,
Rate of loss of heat = K x Mean difference in temperature
`rarr =1=k (55-theta)`
`rarr 4(55-theta)==5(46-theta)`
`rarr 220-4 theta = 230-5 theta`
`rarr theta = 10^(@)` C
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