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A bucket full of hot water cools from 75...

A bucket full of hot water cools from `75^(@)C` to `70^(@)C` in time `T_(1)`, from `70^(@)C` to `65^(@)C` in time `T_(2)` and from `65^(@)C` to `60^(@)C` in time `T_(3)`, then

A

`T_(1)=T_(2)=T_(3)`

B

`T_(1)gtT_(2)gtT_(3)`

C

`T_(1)^(2)gtT_(2)^(2)gtT_(3)^(2)`

D

`T_(1)ltT_(2)ltT_(3)`

Text Solution

Verified by Experts

The correct Answer is:
D
Apply Newton.s law of cooling.
`("hea lost")/("time")`
= K x Mean excess of temperature over surrounding
`T_(1)=("constant")/(72.5 -theta),T_(2)=("cosntant")/(67.5 - theta)`
`therefore T_(1) lt T_(2) lt T_(3)`
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