The ratio of energy of emitted radiation...

The ratio of energy of emitted radiation of a black body at `27^(@)C` and `927^(@)C` is

A

`27:927`

B

`1:256`

C

`1:16`

D

`1:4`

Verified by Experts

The correct Answer is:

B

As `(Q)/(t) prop T^(4)`
`((Q)/(t)_(1))/((Q)/(T)_(2))=T_(1)^(4))/(T_(2)^(4))=300/1200=1:256`

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