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A proton and an alpha-particle enter a u...

A proton and an `alpha-`particle enter a uniform magnetic field moving with the same speed. If the proton takes `25 mu s` to make 5 revolutions, then the periodic time for the `alpha-` particle would be

A

`10 mus `

B

`50 mus `

C

`5 mus `

D

`25 mus`

Text Solution

Verified by Experts

The correct Answer is:
A
Time of one revolution of proton `= (25)/(5) = 5 mus`
Since , `" " T = (2 pi m)/(qB) = (2pi m)/(Bq) = (2pi)/(B) . (m)/(q)`
`therefore" " (T_(1))/(T_(2)) = (m_(1))/(q_(1)) xx (q_(2))/(m_(2))`
`rArr" "T_(2) = (T_(1) xx q_(1) m_(2))/(m_(1) xx q_(2)) = (5 xx q xx 4 m_(1))/(m_(1) xx 2q) = 10 mus `
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