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A helium nucleus makes full rotation in ...

A helium nucleus makes full rotation in a circle of radius 0.8 m in 2.5 seconds. The value of magnetic field B at the centre of the circle will be

A

`10^(19) mu_(0)`

B

`10^(-19) mu_(0)`

C

`2 xx 10^(-10) mu_(0)`

D

`2 xx 10^(10) mu_(0)`

Text Solution

Verified by Experts

The correct Answer is:
B
Current `(i) = ("charge on helium atom ")/("time") = (2 xx (1.6 xx 10^(-19))/(2))`
`I = 1.6 xx 10^(-19)A `
`therefore " " B = (mu_(0).i)/(2r) = (mu_(0) xx 1.6 xx 10^(-19))/(2 xx 0.8) = mu_(0) xx 10^(-19)`
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