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Two particles , each of mass m and char...

Two particles , each of mass ` m` and charge `q`, are attached to the two ends of a light rigid rod of length ` 2 R` . The rod is rotated at constant angular speed about a perpendicular axis passing through its centre. The ratio of the magnitudes of the magnetic moment of the system and its angular momentum about the centre of the rod is

A

`(q)/(m)`

B

`(2q)/(m)`

C

`(q)/(2m)`

D

`(q)/(m)`

Text Solution

Verified by Experts

The correct Answer is:
C
As, `I = 2q = (omega)/(2pi) = (omega w)/( pi)`
`therefore M = IA = (omega w)/(pi) . piR^(2)`
`rArr" " M = q omega R` = Magnetic moment
Now , angles momentum `L = (2R) (mv) = 2R . M R omega`
` = 2 mR^(2) omega" " (therefore V = R omega)`
`therefore " " (M)/(L) = (q omega R^(2) )/(2mR^(2) omega) = (q)/(2m)`
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