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A charged particle of mass m and charge ...

A charged particle of mass m and charge `q` describes circular motion of radius `r` in a uniform magnetic field of strength `B`. The frequency of revolution is

A

`( 3 Bq)/(2pi m)`

B

`(3Bq)/(2pim)`

C

`(2pim)/(3 Bq)`

D

`(Bq)/(2pi m )`

Text Solution

Verified by Experts

The correct Answer is:
D

Force on charge = e vB =e `Romega . B `
Centripetal force ` = mRomega^(2) , omega = 2 pi f`
where , t = frequency
`mRomega^(2) = e R omega B`
`rArr " " mR omega = eRB rArr m omega = eB`
`m. (2 pi f ) = eB rArr r = (eB)/(2 pi m) = (Bq)/(2 pi m)`
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