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An electron ( = 9 xx 10^(-31) kg, e = 1....

An electron `( = 9 xx 10^(-31) kg, e = 1.6 xx 10^(-19))` is moving in a circular in a magnetic field of `1.0 xx 10^(4) Wb// m^(2)` . Its period of revolution is .

A

`7.0 xx 10^(-7) s`

B

`3.5 xx 10^(-7)s`

C

`1.05 xx 10^(-7) s `

D

`2.1 xx 10^(-7) s`

Text Solution

Verified by Experts

The correct Answer is:
B
`T = (2pi m)/(qB) = ( 2 xx 3.14 xx 9 xx 10^(-31))/(1.6 xx 10^(-19) xx 1 xx 10^(-4)) = 3.5 xx 10^(-7)s`
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