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The current flowing in a coil of self-in...

The current flowing in a coil of self-inductance `0.4 mH` is increased by `250mA` in `0.1` sec. the e.m.f. induced will be

A

`-1mV`

B

`-1V`

C

`+1mV`

D

`+1V`

Text Solution

Verified by Experts

The correct Answer is:
A
As, `e= -"L"(dl)/(dt)= -0.4 xx 10^(-3) xx (250 xx 10^(-3))/(0.1)`
`rArr e= -1 mV`
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