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The kinetic energy of a body increases b...

The kinetic energy of a body increases by 300% due to change in its velocity. The momentum increases by

A

1

B

2

C

`sqrt(300%)`

D

`400%`

Text Solution

Verified by Experts

The correct Answer is:
A
Let initial KE=`100alpha`
Final `KE=(100+300)alpha=400alpha`
`(p_(1)^(2))/(p_(2)^(2))=(2mk_(1))/(2mk_(2))=(100alpha)/(400alpha)=(1)/(4)`
`implies (p_(2))/(p_(1))=(2)/(1) implies p_(2)=2p_(1)`
Percentage increament in `p=(p_(2)-p_(1))/(p_(1))xx100`
`=("Change in momentum")/("Original momentum")xx100`
`=(2p_(2)-p_(1))/(p_(1))xx100=100%`.
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