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The temperature of a gas at pressure p a...

The temperature of a gas at pressure p and volume V is `27^(@)C`. Keeping its volume constant, if its temperature is raised to `927^(@)C`, then its pressure will be

A

`2p`

B

`3p`

C

`4p`

D

`6p`

Text Solution

Verified by Experts

The correct Answer is:
C
By charle.s law, `(p_(1))/(T_(1))=(p_(2))/(p_(2))`,
`therefore T_(1)=27+273=300K and T_(2)=927+273=1200K`
`p_(2)=(p_(1)T_(2))/(T_(1))=pxx(1200)/(300) =4p implies p_(2)=4p`
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