The partial pressure of carbon dioxide in the reaction
`CaCO_(3)(s)hArrCaO(s)+CO_(2)(g)`
is `1.017xx10^(-3)` atm at `500^(@)C`. Calculate `K_(p)" at "600^(@)C` for the reaction. `DeltaH` for the reaction is `181KJ"mol"^(-1)` and does not change in the given range of temperature.

Explanation

`P_(CO_(2))=1.017xx10^(-3)` atm
`T=500^(@)C`
`K_(p)=P_(CO_(2))`
`K_(p_(1))=1.017xx10^(-3)`
T = 500 + 273 = 773K
`K_(p_(2))=?" "T=600+273=873K`
`DeltaH^(@)=181KJ"mol"^(-1)`
`log(K_(p_(2))/K_(p_(1)))=(DeltaH^(@))/(2.303R)[(T_(2)-T_(1))/(T_(1)T_(2))]`
`log(K_(p_(2))/(1.017xx10^(-3)))=(181xx10^(3))/(2.303xx8.314)((873-773)/(873xx773))`
`log(K_(p_(2))/(1.017xx10^(-3)))=(181xx10^(3)xx100)/(2.303xx8.314xx873xx773)`
`(K_(p_(2)))/(1.017xx10^(-3))="antilog of"(1.40)`
`(K_(p_(2)))/(1.017xx10^(-3))=25.12`
`rArrK_(p_(2))=25.12xx1.017xx10^(-3)`
`K_(p_(2))=25.54xx10^(-3)`